Solve (21/4+13/5)*26/7=

$$( 2 \frac { 1 } { 4 } + 1 \frac { 3 } { 5 } ) \cdot 2 \frac { 6 } { 7 } =$$

Evaluate

$$11$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\left(\frac{8+1}{4}+\frac{1\times 5+3}{5}\right)\times \frac{2\times 7+6}{7}$$

Add 8 and 1 to get 9.

$$\left(\frac{9}{4}+\frac{1\times 5+3}{5}\right)\times \frac{2\times 7+6}{7}$$

Multiply 1 and 5 to get 5.

$$\left(\frac{9}{4}+\frac{5+3}{5}\right)\times \frac{2\times 7+6}{7}$$

Add 5 and 3 to get 8.

$$\left(\frac{9}{4}+\frac{8}{5}\right)\times \frac{2\times 7+6}{7}$$

Least common multiple of 4 and 5 is 20. Convert \frac{9}{4} and \frac{8}{5} to fractions with denominator 20.

$$\left(\frac{45}{20}+\frac{32}{20}\right)\times \frac{2\times 7+6}{7}$$

Since \frac{45}{20} and \frac{32}{20} have the same denominator, add them by adding their numerators.

$$\frac{45+32}{20}\times \frac{2\times 7+6}{7}$$

Add 45 and 32 to get 77.

$$\frac{77}{20}\times \frac{2\times 7+6}{7}$$

Multiply 2 and 7 to get 14.

$$\frac{77}{20}\times \frac{14+6}{7}$$

Add 14 and 6 to get 20.

$$\frac{77}{20}\times \frac{20}{7}$$

Multiply \frac{77}{20} times \frac{20}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{77\times 20}{20\times 7}$$

Cancel out 20 in both numerator and denominator.

$$\frac{77}{7}$$

Divide 77 by 7 to get 11.

$$11$$

Factor

$$11$$