Solve (21/3+43/4)*2.4

$$( 2 \frac { 1 } { 3 } + 4 \frac { 3 } { 4 } ) \times 2.4$$

Evaluate

$$17$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(\frac{6+1}{3}+\frac{4\times 4+3}{4}\right)\times 2.4$$

Add 6 and 1 to get 7.

$$\left(\frac{7}{3}+\frac{4\times 4+3}{4}\right)\times 2.4$$

Multiply 4 and 4 to get 16.

$$\left(\frac{7}{3}+\frac{16+3}{4}\right)\times 2.4$$

Add 16 and 3 to get 19.

$$\left(\frac{7}{3}+\frac{19}{4}\right)\times 2.4$$

Least common multiple of 3 and 4 is 12. Convert \frac{7}{3} and \frac{19}{4} to fractions with denominator 12.

$$\left(\frac{28}{12}+\frac{57}{12}\right)\times 2.4$$

Since \frac{28}{12} and \frac{57}{12} have the same denominator, add them by adding their numerators.

$$\frac{28+57}{12}\times 2.4$$

Add 28 and 57 to get 85.

$$\frac{85}{12}\times 2.4$$

Convert decimal number 2.4 to fraction \frac{24}{10}. Reduce the fraction \frac{24}{10} to lowest terms by extracting and canceling out 2.

$$\frac{85}{12}\times \frac{12}{5}$$

Multiply \frac{85}{12} times \frac{12}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{85\times 12}{12\times 5}$$

Cancel out 12 in both numerator and denominator.

$$\frac{85}{5}$$

Divide 85 by 5 to get 17.

$$17$$

Factor

$$17$$