Solve (21/12-11/2)+13/4=

$$( 2 \frac { 1 } { 12 } - 1 \frac { 1 } { 2 } ) + 1 \frac { 3 } { 4 } =$$

Evaluate

$$\frac{7}{3}\approx 2.333333333$$

Solution Steps

Multiply 2 and 12 to get 24.

$$\frac{24+1}{12}-\frac{1\times 2+1}{2}+\frac{1\times 4+3}{4}$$

Add 24 and 1 to get 25.

$$\frac{25}{12}-\frac{1\times 2+1}{2}+\frac{1\times 4+3}{4}$$

Multiply 1 and 2 to get 2.

$$\frac{25}{12}-\frac{2+1}{2}+\frac{1\times 4+3}{4}$$

Add 2 and 1 to get 3.

$$\frac{25}{12}-\frac{3}{2}+\frac{1\times 4+3}{4}$$

Least common multiple of 12 and 2 is 12. Convert \frac{25}{12} and \frac{3}{2} to fractions with denominator 12.

$$\frac{25}{12}-\frac{18}{12}+\frac{1\times 4+3}{4}$$

Since \frac{25}{12} and \frac{18}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-18}{12}+\frac{1\times 4+3}{4}$$

Subtract 18 from 25 to get 7.

$$\frac{7}{12}+\frac{1\times 4+3}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{7}{12}+\frac{4+3}{4}$$

Add 4 and 3 to get 7.

$$\frac{7}{12}+\frac{7}{4}$$

Least common multiple of 12 and 4 is 12. Convert \frac{7}{12} and \frac{7}{4} to fractions with denominator 12.

$$\frac{7}{12}+\frac{21}{12}$$

Since \frac{7}{12} and \frac{21}{12} have the same denominator, add them by adding their numerators.

$$\frac{7+21}{12}$$

Add 7 and 21 to get 28.

$$\frac{28}{12}$$

Reduce the fraction \frac{28}{12} to lowest terms by extracting and canceling out 4.

$$\frac{7}{3}$$

Factor

$$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$$