Solve (2*3-2)-4*8div(2+4*5)

$$( 2 \cdot 3 - 2 ) - 4 \cdot 8 \div ( 2 + 4 \cdot 5 )$$

Evaluate

$$\frac{28}{11}\approx 2.545454545$$

Solution Steps

Multiply 2 and 3 to get 6.

$$6-2-\frac{4\times 8}{2+4\times 5}$$

Subtract 2 from 6 to get 4.

$$4-\frac{4\times 8}{2+4\times 5}$$

Multiply 4 and 8 to get 32.

$$4-\frac{32}{2+4\times 5}$$

Multiply 4 and 5 to get 20.

$$4-\frac{32}{2+20}$$

Add 2 and 20 to get 22.

$$4-\frac{32}{22}$$

Reduce the fraction \frac{32}{22} to lowest terms by extracting and canceling out 2.

$$4-\frac{16}{11}$$

Convert 4 to fraction \frac{44}{11}.

$$\frac{44}{11}-\frac{16}{11}$$

Since \frac{44}{11} and \frac{16}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{44-16}{11}$$

Subtract 16 from 44 to get 28.

$$\frac{28}{11}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{11} = 2\frac{6}{11} = 2.5454545454545454$$