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Solve for α_3440
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2\alpha _{3440}-\frac{130}{x}=6020\times 35
Multiply both sides by 35.
2\alpha _{3440}x-130=6020\times 35x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
2\alpha _{3440}x-130=210700x
Multiply 6020 and 35 to get 210700.
2\alpha _{3440}x-130-210700x=0
Subtract 210700x from both sides.
2\alpha _{3440}x-210700x=130
Add 130 to both sides. Anything plus zero gives itself.
\left(2\alpha _{3440}-210700\right)x=130
Combine all terms containing x.
\frac{\left(2\alpha _{3440}-210700\right)x}{2\alpha _{3440}-210700}=\frac{130}{2\alpha _{3440}-210700}
Divide both sides by 2\alpha _{3440}-210700.
x=\frac{130}{2\alpha _{3440}-210700}
Dividing by 2\alpha _{3440}-210700 undoes the multiplication by 2\alpha _{3440}-210700.
x=\frac{65}{\alpha _{3440}-105350}
Divide 130 by 2\alpha _{3440}-210700.
x=\frac{65}{\alpha _{3440}-105350}\text{, }x\neq 0
Variable x cannot be equal to 0.
2\alpha _{3440}-\frac{130}{x}=6020\times 35
Multiply both sides by 35.
2\alpha _{3440}x-130=6020\times 35x
Multiply both sides of the equation by x.
2\alpha _{3440}x-130=210700x
Multiply 6020 and 35 to get 210700.
2\alpha _{3440}x=210700x+130
Add 130 to both sides.
2x\alpha _{3440}=210700x+130
The equation is in standard form.
\frac{2x\alpha _{3440}}{2x}=\frac{210700x+130}{2x}
Divide both sides by 2x.
\alpha _{3440}=\frac{210700x+130}{2x}
Dividing by 2x undoes the multiplication by 2x.
\alpha _{3440}=105350+\frac{65}{x}
Divide 210700x+130 by 2x.