Solve for Y
Y=\frac{1}{3\alpha }
\alpha \neq 0
Solve for α
\alpha =\frac{1}{3Y}
Y\neq 0
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6\alpha Y=2
Multiply 2 and 3 to get 6.
\frac{6\alpha Y}{6\alpha }=\frac{2}{6\alpha }
Divide both sides by 6\alpha .
Y=\frac{2}{6\alpha }
Dividing by 6\alpha undoes the multiplication by 6\alpha .
Y=\frac{1}{3\alpha }
Divide 2 by 6\alpha .
6\alpha Y=2
Multiply 2 and 3 to get 6.
6Y\alpha =2
The equation is in standard form.
\frac{6Y\alpha }{6Y}=\frac{2}{6Y}
Divide both sides by 6Y.
\alpha =\frac{2}{6Y}
Dividing by 6Y undoes the multiplication by 6Y.
\alpha =\frac{1}{3Y}
Divide 2 by 6Y.
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