Solve (2^99-32^20+2^101)div8^33

$$( 2 ^ { 99 } - 32 ^ { 20 } + 2 ^ { 101 } ) \div 8 ^ { 33 }$$

Evaluate

$$3$$

Solution Steps

Calculate 2 to the power of 99 and get 633825300114114700748351602688.

$$\frac{633825300114114700748351602688-32^{20}+2^{101}}{8^{33}}$$

Calculate 32 to the power of 20 and get 1267650600228229401496703205376.

$$\frac{633825300114114700748351602688-1267650600228229401496703205376+2^{101}}{8^{33}}$$

Subtract 1267650600228229401496703205376 from 633825300114114700748351602688 to get -633825300114114700748351602688.

$$\frac{-633825300114114700748351602688+2^{101}}{8^{33}}$$

Calculate 2 to the power of 101 and get 2535301200456458802993406410752.

$$\frac{-633825300114114700748351602688+2535301200456458802993406410752}{8^{33}}$$

Add -633825300114114700748351602688 and 2535301200456458802993406410752 to get 1901475900342344102245054808064.

$$\frac{1901475900342344102245054808064}{8^{33}}$$

Calculate 8 to the power of 33 and get 633825300114114700748351602688.

$$\frac{1901475900342344102245054808064}{633825300114114700748351602688}$$

Divide 1901475900342344102245054808064 by 633825300114114700748351602688 to get 3.

$$3$$

Factor

$$3$$