Solve (2^6)-2^2*[-3div1/5+(-3)^2]

$$( 2 ^ { 6 } ) - 2 ^ { 2 } \times [ - 3 \div \frac { 1 } { 5 } + ( - 3 ) ^ { 2 } ]$$

Evaluate

$$88$$

Solution Steps

Calculate 2 to the power of 6 and get 64.

$$64-2^{2}\left(\frac{-3}{\frac{1}{5}}+\left(-3\right)^{2}\right)$$

Calculate 2 to the power of 2 and get 4.

$$64-4\left(\frac{-3}{\frac{1}{5}}+\left(-3\right)^{2}\right)$$

Divide -3 by \frac{1}{5} by multiplying -3 by the reciprocal of \frac{1}{5}.

$$64-4\left(-3\times 5+\left(-3\right)^{2}\right)$$

Multiply -3 and 5 to get -15.

$$64-4\left(-15+\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$64-4\left(-15+9\right)$$

Add -15 and 9 to get -6.

$$64-4\left(-6\right)$$

Multiply 4 and -6 to get -24.

$$64-\left(-24\right)$$

The opposite of -24 is 24.

$$64+24$$

Add 64 and 24 to get 88.

$$88$$

Factor

$$2^{3}\times 11$$