Solve (2^5-[9(3*4-9)]]:5+3^2*2-(8^2-60)*5

$$( 2 ^ { 5 } - [ 9 ( 3 \cdot 4 - 9 ) ] ] : 5 + 3 ^ { 2 } \cdot 2 - ( 8 ^ { 2 } - 60 ) \cdot 5$$

Evaluate

$$-1$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\frac{32-9\left(3\times 4-9\right)}{5}+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Multiply 3 and 4 to get 12.

$$\frac{32-9\left(12-9\right)}{5}+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Subtract 9 from 12 to get 3.

$$\frac{32-9\times 3}{5}+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Multiply 9 and 3 to get 27.

$$\frac{32-27}{5}+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Subtract 27 from 32 to get 5.

$$\frac{5}{5}+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Divide 5 by 5 to get 1.

$$1+3^{2}\times 2-\left(8^{2}-60\right)\times 5$$

Calculate 3 to the power of 2 and get 9.

$$1+9\times 2-\left(8^{2}-60\right)\times 5$$

Multiply 9 and 2 to get 18.

$$1+18-\left(8^{2}-60\right)\times 5$$

Add 1 and 18 to get 19.

$$19-\left(8^{2}-60\right)\times 5$$

Calculate 8 to the power of 2 and get 64.

$$19-\left(64-60\right)\times 5$$

Subtract 60 from 64 to get 4.

$$19-4\times 5$$

Multiply 4 and 5 to get 20.

$$19-20$$

Subtract 20 from 19 to get -1.

$$-1$$

Factor

$$-1$$