Solve (2^5+12)*2-8^2*1^100+1=

$$( 2 ^ { 5 } + 12 ) \cdot 2 - 8 ^ { 2 } \cdot 1 ^ { 100 } + 1 =$$

Evaluate

$$25$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\left(32+12\right)\times 2-8^{2}\times 1^{100}+1$$

Add 32 and 12 to get 44.

$$44\times 2-8^{2}\times 1^{100}+1$$

Multiply 44 and 2 to get 88.

$$88-8^{2}\times 1^{100}+1$$

Calculate 8 to the power of 2 and get 64.

$$88-64\times 1^{100}+1$$

Calculate 1 to the power of 100 and get 1.

$$88-64\times 1+1$$

Multiply 64 and 1 to get 64.

$$88-64+1$$

Subtract 64 from 88 to get 24.

$$24+1$$

Add 24 and 1 to get 25.

$$25$$

Factor

$$5^{2}$$