Solve (2^5+sqrt{36}):sqrt{2^2+72:6}=

$$( 2 ^ { 5 } + \sqrt { 36 } ) : \sqrt { 2 ^ { 2 } + 72 : 6 } =$$

Evaluate

$$\frac{19}{2}=9.5$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\frac{32+\sqrt{36}}{\sqrt{2^{2}+\frac{72}{6}}}$$

Calculate the square root of 36 and get 6.

$$\frac{32+6}{\sqrt{2^{2}+\frac{72}{6}}}$$

Add 32 and 6 to get 38.

$$\frac{38}{\sqrt{2^{2}+\frac{72}{6}}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{38}{\sqrt{4+\frac{72}{6}}}$$

Divide 72 by 6 to get 12.

$$\frac{38}{\sqrt{4+12}}$$

Add 4 and 12 to get 16.

$$\frac{38}{\sqrt{16}}$$

Calculate the square root of 16 and get 4.

$$\frac{38}{4}$$

Reduce the fraction \frac{38}{4} to lowest terms by extracting and canceling out 2.

$$\frac{19}{2}$$

Factor

$$\frac{19}{2} = 9\frac{1}{2} = 9.5$$