Solve (2^3)^2(2^2-2)=

$$( 2 ^ { 3 } ) ^ { 2 } ( 2 ^ { 2 } - 2 ) =$$

Evaluate

$$128$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$2^{6}\left(2^{2}-2\right)$$

Calculate 2 to the power of 6 and get 64.

$$64\left(2^{2}-2\right)$$

Calculate 2 to the power of 2 and get 4.

$$64\left(4-2\right)$$

Subtract 2 from 4 to get 2.

$$64\times 2$$

Multiply 64 and 2 to get 128.

$$128$$

Factor

$$2^{7}$$