Solve (2^3)^2*(3^2)^3=

$$( 2 ^ { 3 } ) ^ { 2 } \times ( 3 ^ { 2 } ) ^ { 3 } =$$

Evaluate

$$46656$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$2^{6}\times \left(3^{2}\right)^{3}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$2^{6}\times 3^{6}$$

Calculate 2 to the power of 6 and get 64.

$$64\times 3^{6}$$

Calculate 3 to the power of 6 and get 729.

$$64\times 729$$

Multiply 64 and 729 to get 46656.

$$46656$$

Factor

$$2^{6}\times 3^{6}$$