Solve (2^3)^2*2:2^5-2^0=

$$( 2 ^ { 3 } ) ^ { 2 } \cdot 2 : 2 ^ { 5 } - 2 ^ { 0 } =$$

Evaluate

$$3$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\frac{2^{6}\times 2}{2^{5}}-2^{0}$$

To multiply powers of the same base, add their exponents. Add 6 and 1 to get 7.

$$\frac{2^{7}}{2^{5}}-2^{0}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 5 from 7 to get 2.

$$2^{2}-2^{0}$$

Calculate 2 to the power of 2 and get 4.

$$4-2^{0}$$

Calculate 2 to the power of 0 and get 1.

$$4-1$$

Subtract 1 from 4 to get 3.

$$3$$

Factor

$$3$$