Solve (2^2*3^2-4^2):(4^2-11)+(1+3*2)

$$( 2 ^ { 2 } \times 3 ^ { 2 } - 4 ^ { 2 } ) : ( 4 ^ { 2 } - 11 ) + ( 1 + 3 \times 2 )$$

Evaluate

$$11$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4\times 3^{2}-4^{2}}{4^{2}-11}+1+3\times 2$$

Calculate 3 to the power of 2 and get 9.

$$\frac{4\times 9-4^{2}}{4^{2}-11}+1+3\times 2$$

Multiply 4 and 9 to get 36.

$$\frac{36-4^{2}}{4^{2}-11}+1+3\times 2$$

Calculate 4 to the power of 2 and get 16.

$$\frac{36-16}{4^{2}-11}+1+3\times 2$$

Subtract 16 from 36 to get 20.

$$\frac{20}{4^{2}-11}+1+3\times 2$$

Calculate 4 to the power of 2 and get 16.

$$\frac{20}{16-11}+1+3\times 2$$

Subtract 11 from 16 to get 5.

$$\frac{20}{5}+1+3\times 2$$

Divide 20 by 5 to get 4.

$$4+1+3\times 2$$

Add 4 and 1 to get 5.

$$5+3\times 2$$

Multiply 3 and 2 to get 6.

$$5+6$$

Add 5 and 6 to get 11.

$$11$$

Factor

$$11$$