Solve (2^2+3^-3)^2

$$( 2 ^ { 2 } + 3 ^ { - 3 } ) ^ { 2 }$$

Evaluate

$$\frac{11881}{729}\approx 16.297668038$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\left(4+3^{-3}\right)^{2}$$

Calculate 3 to the power of -3 and get \frac{1}{27}.

$$\left(4+\frac{1}{27}\right)^{2}$$

Add 4 and \frac{1}{27} to get \frac{109}{27}.

$$\left(\frac{109}{27}\right)^{2}$$

Calculate \frac{109}{27} to the power of 2 and get \frac{11881}{729}.

$$\frac{11881}{729}$$

Factor

$$\frac{109 ^ {2}}{3 ^ {6}} = 16\frac{217}{729} = 16.29766803840878$$