Solve (2^{-3})^-2(2^-3)^2=2^-3

$$( 2 ^ { - 3 } ) ^ { - 2 } ( 2 ^ { - 3 } ) ^ { 2 } = 2 ^ { - 3 }$$

Verify

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -3 and -2 to get 6.

$$2^{6}\times \left(2^{-3}\right)^{2}=2^{-3}$$

To raise a power to another power, multiply the exponents. Multiply -3 and 2 to get -6.

$$2^{6}\times 2^{-6}=2^{-3}$$

Multiply 2^{6} and 2^{-6} to get 1.

$$1=2^{-3}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$1=\frac{1}{8}$$

Convert 1 to fraction \frac{8}{8}.

$$\frac{8}{8}=\frac{1}{8}$$

Compare \frac{8}{8} and \frac{1}{8}.

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