Solve (2+x)(350-50)+(1+x)(150-40x)

$$( 2 + x ) ( 350 - 50 ) + ( 1 + x ) ( 150 - 40 x )$$

Evaluate

$$750+410x-40x^{2}$$

Solution Steps

Subtract 50 from 350 to get 300.

$$\left(2+x\right)\times 300+\left(1+x\right)\left(150-40x\right)$$

Use the distributive property to multiply 2+x by 300.

$$600+300x+\left(1+x\right)\left(150-40x\right)$$

Apply the distributive property by multiplying each term of 1+x by each term of 150-40x.

$$600+300x+150-40x+150x-40x^{2}$$

Combine -40x and 150x to get 110x.

$$600+300x+150+110x-40x^{2}$$

Add 600 and 150 to get 750.

$$750+300x+110x-40x^{2}$$

Combine 300x and 110x to get 410x.

$$750+410x-40x^{2}$$

Expand

$$750+410x-40x^{2}$$

Solution Steps

Subtract 50 from 350 to get 300.

$$\left(2+x\right)\times 300+\left(1+x\right)\left(150-40x\right)$$

Use the distributive property to multiply 2+x by 300.

$$600+300x+\left(1+x\right)\left(150-40x\right)$$

Apply the distributive property by multiplying each term of 1+x by each term of 150-40x.

$$600+300x+150-40x+150x-40x^{2}$$

Combine -40x and 150x to get 110x.

$$600+300x+150+110x-40x^{2}$$

Add 600 and 150 to get 750.

$$750+300x+110x-40x^{2}$$

Combine 300x and 110x to get 410x.

$$750+410x-40x^{2}$$