Evaluate
\left(x+2\right)^{2}-7
Expand
x^{2}+4x-3
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4+4x+x^{2}-7
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2+x\right)^{2}.
-3+4x+x^{2}
Subtract 7 from 4 to get -3.
4+4x+x^{2}-7
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2+x\right)^{2}.
-3+4x+x^{2}
Subtract 7 from 4 to get -3.
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