Solve (2+a)x^2-3x+1=0text{con}a=-2?

$$( 2 + a ) x ^ { 2 } - 3 x + 1 = 0 \text { con } a = - 2 ?$$

Solve for a, x

$$x=\frac{1}{3}\approx 0.333333333$$

$$a=-2$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$\left(2-2\right)x^{2}-3x+1=0$$

Subtract 2 from 2 to get 0.

$$0x^{2}-3x+1=0$$

Anything times zero gives zero.

$$0-3x+1=0$$

Add 0 and 1 to get 1.

$$1-3x=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-3x=-1$$

Divide both sides by -3.

$$x=\frac{-1}{-3}$$

Fraction \frac{-1}{-3} can be simplified to \frac{1}{3} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{3}$$

The system is now solved.

$$a=-2 x=\frac{1}{3}$$