Solve (2+3i)^2(2-3i)^2

$$( 2 + 3 i ) ^ { 2 } ( 2 - 3 i ) ^ { 2 }$$

Evaluate

$$169$$

Solution Steps

Calculate 2+3i to the power of 2 and get -5+12i.

$$\left(-5+12i\right)\left(2-3i\right)^{2}$$

Calculate 2-3i to the power of 2 and get -5-12i.

$$\left(-5+12i\right)\left(-5-12i\right)$$

Multiply -5+12i and -5-12i to get 169.

$$169$$

Real Part

$$169$$

Solution Steps

Calculate 2+3i to the power of 2 and get -5+12i.

$$Re(\left(-5+12i\right)\left(2-3i\right)^{2})$$

Calculate 2-3i to the power of 2 and get -5-12i.

$$Re(\left(-5+12i\right)\left(-5-12i\right))$$

Multiply -5+12i and -5-12i to get 169.

$$Re(169)$$

The real part of 169 is 169.

$$169$$