Solve (2+1)(2^2+1)(2^4+1)(2^8+1)=

$$( 2 + 1 ) ( 2 ^ { 2 } + 1 ) ( 2 ^ { 4 } + 1 ) ( 2 ^ { 8 } + 1 ) =$$

Evaluate

$$65535$$

Solution Steps

Add 2 and 1 to get 3.

$$3\left(2^{2}+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)$$

Calculate 2 to the power of 2 and get 4.

$$3\left(4+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)$$

Add 4 and 1 to get 5.

$$3\times 5\left(2^{4}+1\right)\left(2^{8}+1\right)$$

Multiply 3 and 5 to get 15.

$$15\left(2^{4}+1\right)\left(2^{8}+1\right)$$

Calculate 2 to the power of 4 and get 16.

$$15\left(16+1\right)\left(2^{8}+1\right)$$

Add 16 and 1 to get 17.

$$15\times 17\left(2^{8}+1\right)$$

Multiply 15 and 17 to get 255.

$$255\left(2^{8}+1\right)$$

Calculate 2 to the power of 8 and get 256.

$$255\left(256+1\right)$$

Add 256 and 1 to get 257.

$$255\times 257$$

Multiply 255 and 257 to get 65535.

$$65535$$

Factor

$$3\times 5\times 17\times 257$$