Solve (2+sqrt{36})^2*[10-8:4*3]

$$( 2 + \sqrt { 36 } ) ^ { 2 } \cdot [ 10 - 8 : 4 \cdot 3 ]$$

Evaluate

$$256$$

Solution Steps

Calculate the square root of 36 and get 6.

$$\left(2+6\right)^{2}\left(10-\frac{8}{4}\times 3\right)$$

Add 2 and 6 to get 8.

$$8^{2}\left(10-\frac{8}{4}\times 3\right)$$

Calculate 8 to the power of 2 and get 64.

$$64\left(10-\frac{8}{4}\times 3\right)$$

Divide 8 by 4 to get 2.

$$64\left(10-2\times 3\right)$$

Multiply 2 and 3 to get 6.

$$64\left(10-6\right)$$

Subtract 6 from 10 to get 4.

$$64\times 4$$

Multiply 64 and 4 to get 256.

$$256$$

Factor

$$2^{8}$$