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2\sqrt{3}-2+\left(\sqrt{3}\right)^{2}-\sqrt{3}
Apply the distributive property by multiplying each term of 2+\sqrt{3} by each term of \sqrt{3}-1.
2\sqrt{3}-2+3-\sqrt{3}
The square of \sqrt{3} is 3.
2\sqrt{3}+1-\sqrt{3}
Add -2 and 3 to get 1.
\sqrt{3}+1
Combine 2\sqrt{3} and -\sqrt{3} to get \sqrt{3}.