Solve (2+1/4)*(6-1/30)=

$$( 2 + \frac { 1 } { 4 } ) \times ( 6 - \frac { 1 } { 30 } ) =$$

Evaluate

$$\frac{537}{40}=13.425$$

Solution Steps

Convert 2 to fraction \frac{8}{4}.

$$\left(\frac{8}{4}+\frac{1}{4}\right)\left(6-\frac{1}{30}\right)$$

Since \frac{8}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{8+1}{4}\left(6-\frac{1}{30}\right)$$

Add 8 and 1 to get 9.

$$\frac{9}{4}\left(6-\frac{1}{30}\right)$$

Convert 6 to fraction \frac{180}{30}.

$$\frac{9}{4}\left(\frac{180}{30}-\frac{1}{30}\right)$$

Since \frac{180}{30} and \frac{1}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9}{4}\times \frac{180-1}{30}$$

Subtract 1 from 180 to get 179.

$$\frac{9}{4}\times \frac{179}{30}$$

Multiply \frac{9}{4} times \frac{179}{30} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 179}{4\times 30}$$

Do the multiplications in the fraction \frac{9\times 179}{4\times 30}.

$$\frac{1611}{120}$$

Reduce the fraction \frac{1611}{120} to lowest terms by extracting and canceling out 3.

$$\frac{537}{40}$$

Factor

$$\frac{3 \cdot 179}{2 ^ {3} \cdot 5} = 13\frac{17}{40} = 13.425$$