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361-304\sqrt{3}+64\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(19-8\sqrt{3}\right)^{2}.
361-304\sqrt{3}+64\times 3
The square of \sqrt{3} is 3.
361-304\sqrt{3}+192
Multiply 64 and 3 to get 192.
553-304\sqrt{3}
Add 361 and 192 to get 553.
361-304\sqrt{3}+64\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(19-8\sqrt{3}\right)^{2}.
361-304\sqrt{3}+64\times 3
The square of \sqrt{3} is 3.
361-304\sqrt{3}+192
Multiply 64 and 3 to get 192.
553-304\sqrt{3}
Add 361 and 192 to get 553.