Solve (18-5*6)^2:(5*2-3*4)*(19-15*1)

$$( 18 - 5 \cdot 6 ) ^ { 2 } : ( 5 \cdot 2 - 3 \cdot 4 ) \cdot ( 19 - 15 \cdot 1 )$$

Evaluate

$$-288$$

Solution Steps

Multiply 5 and 6 to get 30.

$$\frac{\left(18-30\right)^{2}}{5\times 2-3\times 4}\left(19-15\times 1\right)$$

Subtract 30 from 18 to get -12.

$$\frac{\left(-12\right)^{2}}{5\times 2-3\times 4}\left(19-15\times 1\right)$$

Calculate -12 to the power of 2 and get 144.

$$\frac{144}{5\times 2-3\times 4}\left(19-15\times 1\right)$$

Multiply 5 and 2 to get 10.

$$\frac{144}{10-3\times 4}\left(19-15\times 1\right)$$

Multiply 3 and 4 to get 12.

$$\frac{144}{10-12}\left(19-15\times 1\right)$$

Subtract 12 from 10 to get -2.

$$\frac{144}{-2}\left(19-15\times 1\right)$$

Divide 144 by -2 to get -72.

$$-72\left(19-15\right)$$

Subtract 15 from 19 to get 4.

$$-72\times 4$$

Multiply -72 and 4 to get -288.

$$-288$$

Factor

$$-288$$