Solve (18(0)^4-12(0))e^-(0)^3

$$( 18 ( 0 ) ^ { 4 } - 12 ( 0 ) ) e ^ { - ( 0 ) ^ { 3 } }$$

Evaluate

$$0$$

Solution Steps

Calculate 0 to the power of 4 and get 0.

$$\left(18\times 0-12\times 0\right)e^{-0^{3}}$$

Multiply 18 and 0 to get 0.

$$\left(0-12\times 0\right)e^{-0^{3}}$$

Multiply 12 and 0 to get 0.

$$\left(0-0\right)e^{-0^{3}}$$

Subtracting 0 from itself leaves 0.

$$0e^{-0^{3}}$$

Calculate 0 to the power of 3 and get 0.

$$0e^{0}$$

Calculate e to the power of 0 and get 1.

$$0\times 1$$

Multiply 0 and 1 to get 0.

$$0$$

Factor

$$0$$