Solve (16-x)^2-x^2=64

$$( 16 - x ) ^ { 2 } - x ^ { 2 } = 64$$

Solve for x

$$x=6$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(16-x\right)^{2}.

$$256-32x+x^{2}-x^{2}=64$$

Combine x^{2} and -x^{2} to get 0.

$$256-32x=64$$

Subtract 256 from both sides.

$$-32x=64-256$$

Subtract 256 from 64 to get -192.

$$-32x=-192$$

Divide both sides by -32.

$$x=\frac{-192}{-32}$$

Divide -192 by -32 to get 6.

$$x=6$$