Solve (15,1)sqrt{3-x}=2

$$( 15,1 ) \sqrt { 3 - x } = 2$$

Solve for x

$$x=\frac{68003}{22801}\approx 2,98245691$$

Steps for Solving Radical Equations

Divide both sides of the equation by 15,1, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{15,1\sqrt{-x+3}}{15,1}=\frac{2}{15,1}$$

Dividing by 15,1 undoes the multiplication by 15,1.

$$\sqrt{-x+3}=\frac{2}{15,1}$$

Divide 2 by 15,1 by multiplying 2 by the reciprocal of 15,1.

$$\sqrt{-x+3}=\frac{20}{151}$$

Square both sides of the equation.

$$-x+3=\frac{400}{22801}$$

Subtract 3 from both sides of the equation.

$$-x+3-3=\frac{400}{22801}-3$$

Subtracting 3 from itself leaves 0.

$$-x=\frac{400}{22801}-3$$

Subtract 3 from \frac{400}{22801}.

$$-x=-\frac{68003}{22801}$$

Divide both sides by -1.

$$\frac{-x}{-1}=-\frac{\frac{68003}{22801}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=-\frac{\frac{68003}{22801}}{-1}$$

Divide -\frac{68003}{22801} by -1.

$$x=\frac{68003}{22801}$$