Solve (15-4)+3-(12-5*2)+(5+16div4)-5+(10-2^2)

$$( 15 - 4 ) + 3 - ( 12 - 5 \cdot 2 ) + ( 5 + 16 \div 4 ) - 5 + ( 10 - 2 ^ { 2 } )$$

Evaluate

$$22$$

Solution Steps

Subtract 4 from 15 to get 11.

$$11+3-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{2}$$

Add 11 and 3 to get 14.

$$14-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{2}$$

Multiply 5 and 2 to get 10.

$$14-\left(12-10\right)+5+\frac{16}{4}-5+10-2^{2}$$

Subtract 10 from 12 to get 2.

$$14-2+5+\frac{16}{4}-5+10-2^{2}$$

Subtract 2 from 14 to get 12.

$$12+5+\frac{16}{4}-5+10-2^{2}$$

Add 12 and 5 to get 17.

$$17+\frac{16}{4}-5+10-2^{2}$$

Divide 16 by 4 to get 4.

$$17+4-5+10-2^{2}$$

Add 17 and 4 to get 21.

$$21-5+10-2^{2}$$

Subtract 5 from 21 to get 16.

$$16+10-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$16+10-4$$

Subtract 4 from 10 to get 6.

$$16+6$$

Add 16 and 6 to get 22.

$$22$$

Factor

$$2\times 11$$