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196\left(\sqrt{3}\right)^{2}-336\sqrt{3}+144
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(14\sqrt{3}-12\right)^{2}.
196\times 3-336\sqrt{3}+144
The square of \sqrt{3} is 3.
588-336\sqrt{3}+144
Multiply 196 and 3 to get 588.
732-336\sqrt{3}
Add 588 and 144 to get 732.
196\left(\sqrt{3}\right)^{2}-336\sqrt{3}+144
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(14\sqrt{3}-12\right)^{2}.
196\times 3-336\sqrt{3}+144
The square of \sqrt{3} is 3.
588-336\sqrt{3}+144
Multiply 196 and 3 to get 588.
732-336\sqrt{3}
Add 588 and 144 to get 732.