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169-26\sqrt{101}+\left(\sqrt{101}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(13-\sqrt{101}\right)^{2}.
169-26\sqrt{101}+101
The square of \sqrt{101} is 101.
270-26\sqrt{101}
Add 169 and 101 to get 270.
169-26\sqrt{101}+\left(\sqrt{101}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(13-\sqrt{101}\right)^{2}.
169-26\sqrt{101}+101
The square of \sqrt{101} is 101.
270-26\sqrt{101}
Add 169 and 101 to get 270.