Solve (124/5+103/7)*1/3

$$( 12 \frac { 4 } { 5 } + 10 \frac { 3 } { 7 } ) \times \frac { 1 } { 3 }$$

Evaluate

$$\frac{271}{35}\approx 7.742857143$$

Solution Steps

Multiply 12 and 5 to get 60.

$$\left(\frac{60+4}{5}+\frac{10\times 7+3}{7}\right)\times \frac{1}{3}$$

Add 60 and 4 to get 64.

$$\left(\frac{64}{5}+\frac{10\times 7+3}{7}\right)\times \frac{1}{3}$$

Multiply 10 and 7 to get 70.

$$\left(\frac{64}{5}+\frac{70+3}{7}\right)\times \frac{1}{3}$$

Add 70 and 3 to get 73.

$$\left(\frac{64}{5}+\frac{73}{7}\right)\times \frac{1}{3}$$

Least common multiple of 5 and 7 is 35. Convert \frac{64}{5} and \frac{73}{7} to fractions with denominator 35.

$$\left(\frac{448}{35}+\frac{365}{35}\right)\times \frac{1}{3}$$

Since \frac{448}{35} and \frac{365}{35} have the same denominator, add them by adding their numerators.

$$\frac{448+365}{35}\times \frac{1}{3}$$

Add 448 and 365 to get 813.

$$\frac{813}{35}\times \frac{1}{3}$$

Multiply \frac{813}{35} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{813\times 1}{35\times 3}$$

Do the multiplications in the fraction \frac{813\times 1}{35\times 3}.

$$\frac{813}{105}$$

Reduce the fraction \frac{813}{105} to lowest terms by extracting and canceling out 3.

$$\frac{271}{35}$$

Factor

$$\frac{271}{5 \cdot 7} = 7\frac{26}{35} = 7.742857142857143$$