Solve (12:3+1)^2+12:2.3+(1+2)^4=

$$( 12 : 3 + 1 ) ^ { 2 } + 12 : 2.3 + ( 1 + 2 ) ^ { 4 } =$$

Evaluate

$$\frac{2558}{23}\approx 111.217391304$$

Solution Steps

Divide 12 by 3 to get 4.

$$\left(4+1\right)^{2}+\frac{12}{2.3}+\left(1+2\right)^{4}$$

Add 4 and 1 to get 5.

$$5^{2}+\frac{12}{2.3}+\left(1+2\right)^{4}$$

Calculate 5 to the power of 2 and get 25.

$$25+\frac{12}{2.3}+\left(1+2\right)^{4}$$

Expand \frac{12}{2.3} by multiplying both numerator and the denominator by 10.

$$25+\frac{120}{23}+\left(1+2\right)^{4}$$

Add 25 and \frac{120}{23} to get \frac{695}{23}.

$$\frac{695}{23}+\left(1+2\right)^{4}$$

Add 1 and 2 to get 3.

$$\frac{695}{23}+3^{4}$$

Calculate 3 to the power of 4 and get 81.

$$\frac{695}{23}+81$$

Add \frac{695}{23} and 81 to get \frac{2558}{23}.

$$\frac{2558}{23}$$

Factor

$$\frac{2 \cdot 1279}{23} = 111\frac{5}{23} = 111.21739130434783$$