Solve (101)^2=(100)^2+1+2x

$$( 101 ) ^ { 2 } = ( 100 ) ^ { 2 } + 1 + 2 x$$

Solve for x

$$x=100$$

Steps for Solving Linear Equation

Calculate 101 to the power of 2 and get 10201.

$$10201=100^{2}+1+2x$$

Calculate 100 to the power of 2 and get 10000.

$$10201=10000+1+2x$$

Add 10000 and 1 to get 10001.

$$10201=10001+2x$$

Swap sides so that all variable terms are on the left hand side.

$$10001+2x=10201$$

Subtract 10001 from both sides.

$$2x=10201-10001$$

Subtract 10001 from 10201 to get 200.

$$2x=200$$

Divide both sides by 2.

$$x=\frac{200}{2}$$

Divide 200 by 2 to get 100.

$$x=100$$