Solve (100+0.8y)+300

$$( 100 + 0.8 y ) + 300$$

Differentiate w.r.t. y

$$0.8$$

Steps Using Derivative Rule for Sum

Add 100 and 300 to get 400.

$$\frac{\mathrm{d}}{\mathrm{d}y}(400+0.8y)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$0.8y^{1-1}$$

Subtract 1 from 1.

$$0.8y^{0}$$

For any term t except 0, t^{0}=1.

$$0.8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$0.8$$

Evaluate

$$\frac{4y}{5}+400$$

Solution Steps

Add 100 and 300 to get 400.

$$400+0.8y$$