Solve (10-x)^2=10

$$( 10 - x ) ^ { 2 } = 10$$

Solve for x

$$x=10-\sqrt{10}\approx 6.83772234$$

$$x=\sqrt{10}+10\approx 13.16227766$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$-x+10=\sqrt{10} -x+10=-\sqrt{10}$$

Subtract 10 from both sides of the equation.

$$-x+10-10=\sqrt{10}-10 -x+10-10=-\sqrt{10}-10$$

Subtracting 10 from itself leaves 0.

$$-x=\sqrt{10}-10 -x=-\sqrt{10}-10$$

Subtract 10 from \sqrt{10}.

$$-x=\sqrt{10}-10$$

Subtract 10 from -\sqrt{10}.

$$-x=-\sqrt{10}-10$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{\sqrt{10}-10}{-1} \frac{-x}{-1}=\frac{-\sqrt{10}-10}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{\sqrt{10}-10}{-1} x=\frac{-\sqrt{10}-10}{-1}$$

Divide \sqrt{10}-10 by -1.

$$x=10-\sqrt{10}$$

Divide -\sqrt{10}-10 by -1.

$$x=\sqrt{10}+10$$

The equation is now solved.

$$x=10-\sqrt{10} x=\sqrt{10}+10$$