Solve (10-2)div2*3+(6+8)(7-2)-72*2div8

$$( 10 - 2 ) \div 2 \times 3 + ( 6 + 8 ) ( 7 - 2 ) - 72 \times 2 \div 8$$

Evaluate

$$64$$

Solution Steps

Subtract 2 from 10 to get 8.

$$\frac{8}{2}\times 3+\left(6+8\right)\left(7-2\right)-\frac{72\times 2}{8}$$

Divide 8 by 2 to get 4.

$$4\times 3+\left(6+8\right)\left(7-2\right)-\frac{72\times 2}{8}$$

Multiply 4 and 3 to get 12.

$$12+\left(6+8\right)\left(7-2\right)-\frac{72\times 2}{8}$$

Add 6 and 8 to get 14.

$$12+14\left(7-2\right)-\frac{72\times 2}{8}$$

Subtract 2 from 7 to get 5.

$$12+14\times 5-\frac{72\times 2}{8}$$

Multiply 14 and 5 to get 70.

$$12+70-\frac{72\times 2}{8}$$

Add 12 and 70 to get 82.

$$82-\frac{72\times 2}{8}$$

Multiply 72 and 2 to get 144.

$$82-\frac{144}{8}$$

Divide 144 by 8 to get 18.

$$82-18$$

Subtract 18 from 82 to get 64.

$$64$$

Factor

$$2^{6}$$