Solve (10-2*3)^2+4*3*2-(2*2+1)^2

$$( 10 - 2 \times 3 ) ^ { 2 } + 4 \times 3 \times 2 - ( 2 \times 2 + 1 ) ^ { 2 }$$

Evaluate

$$15$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(10-6\right)^{2}+4\times 3\times 2-\left(2\times 2+1\right)^{2}$$

Subtract 6 from 10 to get 4.

$$4^{2}+4\times 3\times 2-\left(2\times 2+1\right)^{2}$$

Calculate 4 to the power of 2 and get 16.

$$16+4\times 3\times 2-\left(2\times 2+1\right)^{2}$$

Multiply 4 and 3 to get 12.

$$16+12\times 2-\left(2\times 2+1\right)^{2}$$

Multiply 12 and 2 to get 24.

$$16+24-\left(2\times 2+1\right)^{2}$$

Add 16 and 24 to get 40.

$$40-\left(2\times 2+1\right)^{2}$$

Multiply 2 and 2 to get 4.

$$40-\left(4+1\right)^{2}$$

Add 4 and 1 to get 5.

$$40-5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$40-25$$

Subtract 25 from 40 to get 15.

$$15$$

Factor

$$3\times 5$$