Solve (10)y=-5/4x+1

$$( 10 ) y = - \frac { 5 } { 4 } x + 1$$

Solve for x

$$x=\frac{4}{5}-8y$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{5}{4}x+1=10y$$

Subtract 1 from both sides.

$$-\frac{5}{4}x=10y-1$$

Divide both sides of the equation by -\frac{5}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{5}{4}x}{-\frac{5}{4}}=\frac{10y-1}{-\frac{5}{4}}$$

Dividing by -\frac{5}{4} undoes the multiplication by -\frac{5}{4}.

$$x=\frac{10y-1}{-\frac{5}{4}}$$

Divide 10y-1 by -\frac{5}{4} by multiplying 10y-1 by the reciprocal of -\frac{5}{4}.

$$x=\frac{4}{5}-8y$$

Solve for y

$$y=-\frac{x}{8}+\frac{1}{10}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$10y=-\frac{5x}{4}+1$$

Divide both sides by 10.

$$\frac{10y}{10}=\frac{-\frac{5x}{4}+1}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$y=\frac{-\frac{5x}{4}+1}{10}$$

Divide -\frac{5x}{4}+1 by 10.

$$y=-\frac{x}{8}+\frac{1}{10}$$