Solve (10)755mmHg*1.15dm*273K/295K*760mmHg=

$$( 10 ) \frac { 755 mmHg \times 1.15 dm \times 273 K } { 295 K \times 760 mmHg } =$$

Evaluate

$$\frac{948129dm}{89680}$$

Solution Steps

Multiply m and m to get m^{2}.

$$10\times \frac{755m^{2}Hg\times 1.15dm\times 273K}{295K\times 760mmHg}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$10\times \frac{755m^{3}Hg\times 1.15d\times 273K}{295K\times 760mmHg}$$

Multiply m and m to get m^{2}.

$$10\times \frac{755m^{3}Hg\times 1.15d\times 273K}{295K\times 760m^{2}Hg}$$

Cancel out 5HKgm^{2} in both numerator and denominator.

$$10\times \frac{1.15\times 151\times 273dm}{59\times 760}$$

Multiply 1.15 and 151 to get 173.65.

$$10\times \frac{173.65\times 273dm}{59\times 760}$$

Multiply 173.65 and 273 to get 47406.45.

$$10\times \frac{47406.45dm}{59\times 760}$$

Multiply 59 and 760 to get 44840.

$$10\times \frac{47406.45dm}{44840}$$

Divide 47406.45dm by 44840 to get \frac{948129}{896800}dm.

$$10\times \frac{948129}{896800}dm$$

Multiply 10 and \frac{948129}{896800} to get \frac{948129}{89680}.

$$\frac{948129}{89680}dm$$

Differentiate w.r.t. d

$$\frac{948129m}{89680}$$