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100\left(\sqrt{6}\right)^{2}+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(10\sqrt{6}+10\sqrt{2}\right)^{2}.
100\times 6+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
The square of \sqrt{6} is 6.
600+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Multiply 100 and 6 to get 600.
600+200\sqrt{2}\sqrt{3}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
600+200\times 2\sqrt{3}+100\left(\sqrt{2}\right)^{2}
Multiply \sqrt{2} and \sqrt{2} to get 2.
600+400\sqrt{3}+100\left(\sqrt{2}\right)^{2}
Multiply 200 and 2 to get 400.
600+400\sqrt{3}+100\times 2
The square of \sqrt{2} is 2.
600+400\sqrt{3}+200
Multiply 100 and 2 to get 200.
800+400\sqrt{3}
Add 600 and 200 to get 800.
100\left(\sqrt{6}\right)^{2}+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(10\sqrt{6}+10\sqrt{2}\right)^{2}.
100\times 6+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
The square of \sqrt{6} is 6.
600+200\sqrt{6}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Multiply 100 and 6 to get 600.
600+200\sqrt{2}\sqrt{3}\sqrt{2}+100\left(\sqrt{2}\right)^{2}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
600+200\times 2\sqrt{3}+100\left(\sqrt{2}\right)^{2}
Multiply \sqrt{2} and \sqrt{2} to get 2.
600+400\sqrt{3}+100\left(\sqrt{2}\right)^{2}
Multiply 200 and 2 to get 400.
600+400\sqrt{3}+100\times 2
The square of \sqrt{2} is 2.
600+400\sqrt{3}+200
Multiply 100 and 2 to get 200.
800+400\sqrt{3}
Add 600 and 200 to get 800.