Solve (10*12)+2(6div13)+(6*10)

$$( 10 \cdot 12 ) + 2 ( 6 \div 13 ) + ( 6 \cdot 10 )$$

Evaluate

$$\frac{2352}{13}\approx 180.923076923$$

Solution Steps

Multiply 10 and 12 to get 120. Multiply 6 and 10 to get 60.

$$120+2\times \frac{6}{13}+60$$

Express 2\times \frac{6}{13} as a single fraction.

$$120+\frac{2\times 6}{13}+60$$

Multiply 2 and 6 to get 12.

$$120+\frac{12}{13}+60$$

Convert 120 to fraction \frac{1560}{13}.

$$\frac{1560}{13}+\frac{12}{13}+60$$

Since \frac{1560}{13} and \frac{12}{13} have the same denominator, add them by adding their numerators.

$$\frac{1560+12}{13}+60$$

Add 1560 and 12 to get 1572.

$$\frac{1572}{13}+60$$

Convert 60 to fraction \frac{780}{13}.

$$\frac{1572}{13}+\frac{780}{13}$$

Since \frac{1572}{13} and \frac{780}{13} have the same denominator, add them by adding their numerators.

$$\frac{1572+780}{13}$$

Add 1572 and 780 to get 2352.

$$\frac{2352}{13}$$

Factor

$$\frac{2 ^ {4} \cdot 3 \cdot 7 ^ {2}}{13} = 180\frac{12}{13} = 180.92307692307693$$