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\frac{\left(\frac{10+10}{3}-2\right)\times \frac{1}{8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Since \frac{10}{3} and \frac{10}{3} have the same denominator, add them by adding their numerators.
\frac{\left(\frac{20}{3}-2\right)\times \frac{1}{8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Add 10 and 10 to get 20.
\frac{\left(\frac{20}{3}-\frac{6}{3}\right)\times \frac{1}{8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Convert 2 to fraction \frac{6}{3}.
\frac{\frac{20-6}{3}\times \frac{1}{8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Since \frac{20}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{14}{3}\times \frac{1}{8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Subtract 6 from 20 to get 14.
\frac{\frac{14\times 1}{3\times 8}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Multiply \frac{14}{3} times \frac{1}{8} by multiplying numerator times numerator and denominator times denominator.
\frac{\frac{14}{24}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Do the multiplications in the fraction \frac{14\times 1}{3\times 8}.
\frac{\frac{7}{12}}{\frac{\frac{2}{3}}{\frac{8}{11}}}
Reduce the fraction \frac{14}{24} to lowest terms by extracting and canceling out 2.
\frac{\frac{7}{12}}{\frac{2}{3}\times \frac{11}{8}}
Divide \frac{2}{3} by \frac{8}{11} by multiplying \frac{2}{3} by the reciprocal of \frac{8}{11}.
\frac{\frac{7}{12}}{\frac{2\times 11}{3\times 8}}
Multiply \frac{2}{3} times \frac{11}{8} by multiplying numerator times numerator and denominator times denominator.
\frac{\frac{7}{12}}{\frac{22}{24}}
Do the multiplications in the fraction \frac{2\times 11}{3\times 8}.
\frac{\frac{7}{12}}{\frac{11}{12}}
Reduce the fraction \frac{22}{24} to lowest terms by extracting and canceling out 2.
\frac{7}{12}\times \frac{12}{11}
Divide \frac{7}{12} by \frac{11}{12} by multiplying \frac{7}{12} by the reciprocal of \frac{11}{12}.
\frac{7\times 12}{12\times 11}
Multiply \frac{7}{12} times \frac{12}{11} by multiplying numerator times numerator and denominator times denominator.
\frac{7}{11}
Cancel out 12 in both numerator and denominator.