Solve (1,75+21/3)*15/7

$$( 1,75 + 2 \frac { 1 } { 3 } ) \cdot 1 \frac { 5 } { 7 }$$

Evaluate

$$7$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(1,75+\frac{6+1}{3}\right)\times \frac{1\times 7+5}{7}$$

Add 6 and 1 to get 7.

$$\left(1,75+\frac{7}{3}\right)\times \frac{1\times 7+5}{7}$$

Convert decimal number 1,75 to fraction \frac{175}{100}. Reduce the fraction \frac{175}{100} to lowest terms by extracting and canceling out 25.

$$\left(\frac{7}{4}+\frac{7}{3}\right)\times \frac{1\times 7+5}{7}$$

Least common multiple of 4 and 3 is 12. Convert \frac{7}{4} and \frac{7}{3} to fractions with denominator 12.

$$\left(\frac{21}{12}+\frac{28}{12}\right)\times \frac{1\times 7+5}{7}$$

Since \frac{21}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{21+28}{12}\times \frac{1\times 7+5}{7}$$

Add 21 and 28 to get 49.

$$\frac{49}{12}\times \frac{1\times 7+5}{7}$$

Multiply 1 and 7 to get 7.

$$\frac{49}{12}\times \frac{7+5}{7}$$

Add 7 and 5 to get 12.

$$\frac{49}{12}\times \frac{12}{7}$$

Multiply \frac{49}{12} times \frac{12}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{49\times 12}{12\times 7}$$

Cancel out 12 in both numerator and denominator.

$$\frac{49}{7}$$

Divide 49 by 7 to get 7.

$$7$$

Factor

$$7$$