Solve (1,26:2,4):11/3+5/6*(0,8-1,5*0,8)

$$( 1,26 : 2,4 ) : \frac { 11 } { 3 } + \frac { 5 } { 6 } \cdot ( 0,8 - 1,5 \cdot 0,8 )$$

Evaluate

$$-\frac{251}{1320}\approx -0,190151515$$

Solution Steps

Divide \frac{1,26}{2,4} by \frac{11}{3} by multiplying \frac{1,26}{2,4} by the reciprocal of \frac{11}{3}.

$$\frac{1,26\times 3}{2,4\times 11}+\frac{5}{6}\left(0,8-1,5\times 0,8\right)$$

Multiply 1,26 and 3 to get 3,78.

$$\frac{3,78}{2,4\times 11}+\frac{5}{6}\left(0,8-1,5\times 0,8\right)$$

Multiply 2,4 and 11 to get 26,4.

$$\frac{3,78}{26,4}+\frac{5}{6}\left(0,8-1,5\times 0,8\right)$$

Expand \frac{3,78}{26,4} by multiplying both numerator and the denominator by 100.

$$\frac{378}{2640}+\frac{5}{6}\left(0,8-1,5\times 0,8\right)$$

Reduce the fraction \frac{378}{2640} to lowest terms by extracting and canceling out 6.

$$\frac{63}{440}+\frac{5}{6}\left(0,8-1,5\times 0,8\right)$$

Multiply 1,5 and 0,8 to get 1,2.

$$\frac{63}{440}+\frac{5}{6}\left(0,8-1,2\right)$$

Subtract 1,2 from 0,8 to get -0,4.

$$\frac{63}{440}+\frac{5}{6}\left(-0,4\right)$$

Convert decimal number -0,4 to fraction -\frac{4}{10}. Reduce the fraction -\frac{4}{10} to lowest terms by extracting and canceling out 2.

$$\frac{63}{440}+\frac{5}{6}\left(-\frac{2}{5}\right)$$

Multiply \frac{5}{6} times -\frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{63}{440}+\frac{5\left(-2\right)}{6\times 5}$$

Cancel out 5 in both numerator and denominator.

$$\frac{63}{440}+\frac{-2}{6}$$

Reduce the fraction \frac{-2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{63}{440}-\frac{1}{3}$$

Least common multiple of 440 and 3 is 1320. Convert \frac{63}{440} and \frac{1}{3} to fractions with denominator 1320.

$$\frac{189}{1320}-\frac{440}{1320}$$

Since \frac{189}{1320} and \frac{440}{1320} have the same denominator, subtract them by subtracting their numerators.

$$\frac{189-440}{1320}$$

Subtract 440 from 189 to get -251.

$$-\frac{251}{1320}$$

Factor

$$-\frac{251}{1320} = -0.19015151515151515$$