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1\left(-4\right)+1\times \left(3i\right)-i\left(-4\right)-3i^{2}
Multiply complex numbers 1-i and -4+3i like you multiply binomials.
1\left(-4\right)+1\times \left(3i\right)-i\left(-4\right)-3\left(-1\right)
By definition, i^{2} is -1.
-4+3i+4i+3
Do the multiplications.
-4+3+\left(3+4\right)i
Combine the real and imaginary parts.
-1+7i
Do the additions.
Re(1\left(-4\right)+1\times \left(3i\right)-i\left(-4\right)-3i^{2})
Multiply complex numbers 1-i and -4+3i like you multiply binomials.
Re(1\left(-4\right)+1\times \left(3i\right)-i\left(-4\right)-3\left(-1\right))
By definition, i^{2} is -1.
Re(-4+3i+4i+3)
Do the multiplications in 1\left(-4\right)+1\times \left(3i\right)-i\left(-4\right)-3\left(-1\right).
Re(-4+3+\left(3+4\right)i)
Combine the real and imaginary parts in -4+3i+4i+3.
Re(-1+7i)
Do the additions in -4+3+\left(3+4\right)i.
-1
The real part of -1+7i is -1.