Solve (1-2b^4)-(7b+5b^3)-(1-6b^3)

$$( 1 - 2 b ^ { 4 } ) - ( 7 b + 5 b ^ { 3 } ) - ( 1 - 6 b ^ { 3 } )$$

Evaluate

$$b\left(-2b^{3}+b^{2}-7\right)$$

Solution Steps

To find the opposite of 7b+5b^{3}, find the opposite of each term.

$$1-2b^{4}-7b-5b^{3}-\left(1-6b^{3}\right)$$

To find the opposite of 1-6b^{3}, find the opposite of each term.

$$1-2b^{4}-7b-5b^{3}-1+6b^{3}$$

Subtract 1 from 1 to get 0.

$$-2b^{4}-7b-5b^{3}+6b^{3}$$

Combine -5b^{3} and 6b^{3} to get b^{3}.

$$-2b^{4}-7b+b^{3}$$

Expand

$$-2b^{4}+b^{3}-7b$$

Solution Steps

To find the opposite of 7b+5b^{3}, find the opposite of each term.

$$1-2b^{4}-7b-5b^{3}-\left(1-6b^{3}\right)$$

To find the opposite of 1-6b^{3}, find the opposite of each term.

$$1-2b^{4}-7b-5b^{3}-1+6b^{3}$$

Subtract 1 from 1 to get 0.

$$-2b^{4}-7b-5b^{3}+6b^{3}$$

Combine -5b^{3} and 6b^{3} to get b^{3}.

$$-2b^{4}-7b+b^{3}$$