Solve (1-2)^2+(1/2+1)^2-5*1,2^2

$$( 1 - 2 ) ^ { 2 } + ( \frac { 1 } { 2 } + 1 ) ^ { 2 } - 5 \cdot 1,2 ^ { 2 }$$

Evaluate

$$-\frac{67}{4}=-16,75$$

Solution Steps

Subtract 2 from 1 to get -1.

$$\left(-1\right)^{2}+\left(\frac{1}{2}+1\right)^{2}-5\times 1\times 2^{2}$$

Calculate -1 to the power of 2 and get 1.

$$1+\left(\frac{1}{2}+1\right)^{2}-5\times 1\times 2^{2}$$

Add \frac{1}{2} and 1 to get \frac{3}{2}.

$$1+\left(\frac{3}{2}\right)^{2}-5\times 1\times 2^{2}$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$1+\frac{9}{4}-5\times 1\times 2^{2}$$

Add 1 and \frac{9}{4} to get \frac{13}{4}.

$$\frac{13}{4}-5\times 1\times 2^{2}$$

Multiply 5 and 1 to get 5.

$$\frac{13}{4}-5\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{13}{4}-5\times 4$$

Multiply 5 and 4 to get 20.

$$\frac{13}{4}-20$$

Subtract 20 from \frac{13}{4} to get -\frac{67}{4}.

$$-\frac{67}{4}$$

Factor

$$-\frac{67}{4} = -16\frac{3}{4} = -16.75$$